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Chapter 7 — The Unit Circle: Sine and Cosine Functions

Trigonometry literally means “triangle measurement,” but its power extends far beyond triangles. By connecting angles to the unit circle, we define the sine and cosine functions for all real numbers — enabling us to model everything from sound waves to planetary orbits. This chapter builds the foundation.


Table of Contents


Glossary

Term Definition
Angle Formed by rotating a ray from an initial side to a terminal side
Standard position Vertex at the origin, initial side along the positive $x$-axis
Degree $1/360$ of a full rotation; symbol: °
Radian The angle subtended by an arc equal in length to the radius; $2\pi$ rad $= 360°$
Coterminal angles Angles sharing the same terminal side (differ by multiples of $360°$ or $2\pi$)
Reference angle The acute angle between the terminal side and the $x$-axis
Unit circle The circle $x^2 + y^2 = 1$ centered at the origin
Sine $\sin\theta = y$-coordinate on the unit circle
Cosine $\cos\theta = x$-coordinate on the unit circle
Tangent $\tan\theta = \sin\theta / \cos\theta$
Cosecant $\csc\theta = 1/\sin\theta$
Secant $\sec\theta = 1/\cos\theta$
Cotangent $\cot\theta = \cos\theta / \sin\theta$
Arc length $s = r\theta$ (with $\theta$ in radians)
Sector area $A = \tfrac{1}{2}r^2\theta$ (with $\theta$ in radians)

1 — Angles

1.1 Angles in Standard Position

An angle is in standard position when:

  • Its vertex is at the origin.
  • Its initial side lies along the positive $x$-axis.
  • Its terminal side is the ray after rotation.

Positive angles: counterclockwise rotation.
Negative angles: clockwise rotation.

1.2 Degree Measure

One full rotation = $360°$

Common angle types:

  • Acute: $0° < \theta < 90°$
  • Right: $\theta = 90°$
  • Obtuse: $90° < \theta < 180°$
  • Straight: $\theta = 180°$
  • Reflex: $180° < \theta < 360°$

Degrees-Minutes-Seconds (DMS): $1° = 60’$ (minutes), $1’ = 60’’$ (seconds).

1.3 Radian Measure

One radian is the angle subtended at the center of a circle by an arc whose length equals the radius.

\(2\pi \text{ radians} = 360° \qquad \Rightarrow \qquad \pi \text{ rad} = 180°\)

Why radians? Radians make calculus formulas clean. With radians:

  • Arc length: $s = r\theta$ (simple!)
  • $\dfrac{d}{dx}\sin x = \cos x$ (only works in radians)
  • $\lim_{x \to 0} \dfrac{\sin x}{x} = 1$ (only in radians)

1.4 Converting Between Degrees and Radians

\[\text{Degrees} \to \text{Radians:} \quad \theta_{\text{rad}} = \theta_{\text{deg}} \times \frac{\pi}{180}\]

\(\text{Radians} \to \text{Degrees:} \quad \theta_{\text{deg}} = \theta_{\text{rad}} \times \frac{180}{\pi}\)

| Degrees | Radians | |———|———| | $30°$ | $\dfrac{\pi}{6}$ | | $45°$ | $\dfrac{\pi}{4}$ | | $60°$ | $\dfrac{\pi}{3}$ | | $90°$ | $\dfrac{\pi}{2}$ | | $120°$ | $\dfrac{2\pi}{3}$ | | $135°$ | $\dfrac{3\pi}{4}$ | | $150°$ | $\dfrac{5\pi}{6}$ | | $180°$ | $\pi$ | | $270°$ | $\dfrac{3\pi}{2}$ | | $360°$ | $2\pi$ |

1.5 Coterminal Angles

Two angles are coterminal if they share the same terminal side.

\(\theta_{\text{coterminal}} = \theta + 360°n \quad \text{(degrees)}\) \(\theta_{\text{coterminal}} = \theta + 2\pi n \quad \text{(radians)}\)

where $n$ is any integer.

Example: Find a positive coterminal angle for $-150°$.

$-150° + 360° = 210°$ ✓

Example: Find a coterminal angle in $[0, 2\pi)$ for $\dfrac{17\pi}{4}$.

$\dfrac{17\pi}{4} - 2\pi = \dfrac{17\pi}{4} - \dfrac{8\pi}{4} = \dfrac{9\pi}{4}$ → still $> 2\pi$

$\dfrac{9\pi}{4} - 2\pi = \dfrac{9\pi}{4} - \dfrac{8\pi}{4} = \dfrac{\pi}{4}$ ✓

1.6 Arc Length and Area of a Sector

For a circle of radius $r$ and central angle $\theta$ (in radians):

\[\text{Arc length:} \quad s = r\theta\]

\(\text{Sector area:} \quad A = \frac{1}{2}r^2\theta\)

Example: Find the arc length and sector area for $r = 10$ cm and $\theta = \dfrac{2\pi}{3}$.

$s = 10 \cdot \dfrac{2\pi}{3} = \dfrac{20\pi}{3} \approx 20.94$ cm

$A = \dfrac{1}{2}(100)\left(\dfrac{2\pi}{3}\right) = \dfrac{100\pi}{3} \approx 104.72$ cm²

These formulas require $\theta$ in radians. If given degrees, convert first!

1.7 Linear and Angular Speed

  • Angular speed: $\omega = \dfrac{\theta}{t}$ (radians per unit time)
  • Linear speed: $v = \dfrac{s}{t} = r\omega$ (distance per unit time along the arc)

Relationship: $v = r\omega$

Example: A wheel of radius 2 feet rotates at 150 rpm. Find the linear speed of a point on the rim.

$\omega = 150 \times 2\pi = 300\pi$ rad/min

$v = r\omega = 2 \times 300\pi = 600\pi \approx 1884.96$ ft/min


2 — Right Triangle Trigonometry

2.1 The Six Trigonometric Ratios

For a right triangle with angle $\theta$, opposite side ($O$), adjacent side ($A$), and hypotenuse ($H$):

| Function | Ratio | Mnemonic | |———-|——-|———-| | $\sin\theta$ | $\dfrac{O}{H}$ | SOH | | $\cos\theta$ | $\dfrac{A}{H}$ | CAH | | $\tan\theta$ | $\dfrac{O}{A}$ | TOA | | $\csc\theta$ | $\dfrac{H}{O}$ | reciprocal of sine | | $\sec\theta$ | $\dfrac{H}{A}$ | reciprocal of cosine | | $\cot\theta$ | $\dfrac{A}{O}$ | reciprocal of tangent |

SOH-CAH-TOA — memorize this. Every right-triangle trig problem uses it.

2.2 Special Right Triangles (30-60-90 and 45-45-90)

45-45-90 Triangle: Sides in ratio $1 : 1 : \sqrt{2}$

Angle sin cos tan
$45°$ $\dfrac{\sqrt{2}}{2}$ $\dfrac{\sqrt{2}}{2}$ $1$

30-60-90 Triangle: Sides in ratio $1 : \sqrt{3} : 2$

| Angle | sin | cos | tan | |——-|—–|—–|—–| | $30°$ | $\dfrac{1}{2}$ | $\dfrac{\sqrt{3}}{2}$ | $\dfrac{1}{\sqrt{3}} = \dfrac{\sqrt{3}}{3}$ | | $60°$ | $\dfrac{\sqrt{3}}{2}$ | $\dfrac{1}{2}$ | $\sqrt{3}$ |

2.3 Evaluating Trig Functions for Special Angles

Build a table from the special triangles and quadrantal angles:

| $\theta$ | $0°$ | $30°$ | $45°$ | $60°$ | $90°$ | |—|—|—|—|—|—| | $\sin\theta$ | $0$ | $\dfrac{1}{2}$ | $\dfrac{\sqrt{2}}{2}$ | $\dfrac{\sqrt{3}}{2}$ | $1$ | | $\cos\theta$ | $1$ | $\dfrac{\sqrt{3}}{2}$ | $\dfrac{\sqrt{2}}{2}$ | $\dfrac{1}{2}$ | $0$ | | $\tan\theta$ | $0$ | $\dfrac{\sqrt{3}}{3}$ | $1$ | $\sqrt{3}$ | undef. |

Pattern for sine: At $0°, 30°, 45°, 60°, 90°$, sine takes values $\dfrac{\sqrt{0}}{2}, \dfrac{\sqrt{1}}{2}, \dfrac{\sqrt{2}}{2}, \dfrac{\sqrt{3}}{2}, \dfrac{\sqrt{4}}{2}$. The numerator is $\sqrt{0}, \sqrt{1}, \sqrt{2}, \sqrt{3}, \sqrt{4}$. Cosine is the same sequence reversed.

2.4 Cofunction Identities

Cofunction Identities: If $\alpha + \beta = 90°$ (or $\alpha + \beta = \tfrac{\pi}{2}$), then:

\(\sin\alpha = \cos\beta, \qquad \cos\alpha = \sin\beta\) \(\tan\alpha = \cot\beta, \qquad \sec\alpha = \csc\beta\)

In other words:

\(\sin(90° - \theta) = \cos\theta, \qquad \cos(90° - \theta) = \sin\theta\)


3 — The Unit Circle

3.1 Definition and Key Coordinates

The unit circle is the circle of radius 1 centered at the origin:

\[x^2 + y^2 = 1\]

Every point on the unit circle can be written as $(\cos\theta, \sin\theta)$ where $\theta$ is the angle from the positive $x$-axis.

3.2 Sine and Cosine on the Unit Circle

For any angle $\theta$, the terminal side intersects the unit circle at a point $(x, y)$. Then:

\[\cos\theta = x \qquad \sin\theta = y\]

This definition extends sine and cosine to all real numbers, not just acute angles.

Since every point on the unit circle satisfies $x^2 + y^2 = 1$:

\[\cos^2\theta + \sin^2\theta = 1 \quad \text{(Pythagorean Identity)}\]

3.3 The Complete Unit Circle Table

Angle (deg) Angle (rad) $\cos\theta$ $\sin\theta$ Quadrant
$0°$ $0$ $1$ $0$
$30°$ $\dfrac{\pi}{6}$ $\dfrac{\sqrt{3}}{2}$ $\dfrac{1}{2}$ I
$45°$ $\dfrac{\pi}{4}$ $\dfrac{\sqrt{2}}{2}$ $\dfrac{\sqrt{2}}{2}$ I
$60°$ $\dfrac{\pi}{3}$ $\dfrac{1}{2}$ $\dfrac{\sqrt{3}}{2}$ I
$90°$ $\dfrac{\pi}{2}$ $0$ $1$
$120°$ $\dfrac{2\pi}{3}$ $-\dfrac{1}{2}$ $\dfrac{\sqrt{3}}{2}$ II
$135°$ $\dfrac{3\pi}{4}$ $-\dfrac{\sqrt{2}}{2}$ $\dfrac{\sqrt{2}}{2}$ II
$150°$ $\dfrac{5\pi}{6}$ $-\dfrac{\sqrt{3}}{2}$ $\dfrac{1}{2}$ II
$180°$ $\pi$ $-1$ $0$
$210°$ $\dfrac{7\pi}{6}$ $-\dfrac{\sqrt{3}}{2}$ $-\dfrac{1}{2}$ III
$225°$ $\dfrac{5\pi}{4}$ $-\dfrac{\sqrt{2}}{2}$ $-\dfrac{\sqrt{2}}{2}$ III
$240°$ $\dfrac{4\pi}{3}$ $-\dfrac{1}{2}$ $-\dfrac{\sqrt{3}}{2}$ III
$270°$ $\dfrac{3\pi}{2}$ $0$ $-1$
$300°$ $\dfrac{5\pi}{3}$ $\dfrac{1}{2}$ $-\dfrac{\sqrt{3}}{2}$ IV
$315°$ $\dfrac{7\pi}{4}$ $\dfrac{\sqrt{2}}{2}$ $-\dfrac{\sqrt{2}}{2}$ IV
$330°$ $\dfrac{11\pi}{6}$ $\dfrac{\sqrt{3}}{2}$ $-\dfrac{1}{2}$ IV
$360°$ $2\pi$ $1$ $0$

You don’t need to memorize all 16 entries. Memorize Quadrant I (the first four nonzero angles) and use reference angles + quadrant signs to find the rest.

3.4 Reference Angles

The reference angle $\theta’$ for an angle $\theta$ in standard position is the acute angle formed between the terminal side and the $x$-axis.

| Quadrant | Reference angle formula | |———-|———————-| | I ($0° < \theta < 90°$) | $\theta’ = \theta$ | | II ($90° < \theta < 180°$) | $\theta’ = 180° - \theta$ | | III ($180° < \theta < 270°$) | $\theta’ = \theta - 180°$ | | IV ($270° < \theta < 360°$) | $\theta’ = 360° - \theta$ |

The trig function values at $\theta$ have the same magnitude as at $\theta’$; only the sign might change (based on the quadrant).

Example: Find $\sin(240°)$.

$240°$ is in Q III. Reference angle $= 240° - 180° = 60°$.

In Q III, sine is negative.

$\sin(240°) = -\sin(60°) = -\dfrac{\sqrt{3}}{2}$ ✓

3.5 Signs of Trig Functions by Quadrant

“All Students Take Calculus” (ASTC):

| Quadrant | sin | cos | tan | |———-|—–|—–|—–| | I | + | + | + | (All positive) | II | + | − | − | (Sine positive) | III | − | − | + | (Tangent positive) | IV | − | + | − | (Cosine positive)

Why does this work? On the unit circle, $\cos\theta = x$ and $\sin\theta = y$. In Q II, $x < 0$ and $y > 0$, so cosine is negative and sine is positive. Similar reasoning applies to all quadrants.


4 — The Other Trigonometric Functions

4.1 Tangent, Cotangent, Secant, Cosecant

| Function | Definition | Domain restriction | |———-|———–|——————-| | $\tan\theta = \dfrac{\sin\theta}{\cos\theta}$ | $= \dfrac{y}{x}$ on unit circle | $\cos\theta \ne 0$ ($\theta \ne 90° + 180°n$) | | $\cot\theta = \dfrac{\cos\theta}{\sin\theta}$ | $= \dfrac{x}{y}$ on unit circle | $\sin\theta \ne 0$ ($\theta \ne 180°n$) | | $\sec\theta = \dfrac{1}{\cos\theta}$ | $= \dfrac{1}{x}$ on unit circle | $\cos\theta \ne 0$ | | $\csc\theta = \dfrac{1}{\sin\theta}$ | $= \dfrac{1}{y}$ on unit circle | $\sin\theta \ne 0$ |

4.2 Evaluating the Other Trig Functions

Example: Find all six trig functions of $\theta = \dfrac{5\pi}{4}$.

This is in Q III, reference angle $= \dfrac{5\pi}{4} - \pi = \dfrac{\pi}{4}$. In Q III, both sin and cos are negative.

$\sin\dfrac{5\pi}{4} = -\dfrac{\sqrt{2}}{2}$, $\quad \cos\dfrac{5\pi}{4} = -\dfrac{\sqrt{2}}{2}$

$\tan\dfrac{5\pi}{4} = \dfrac{-\sqrt{2}/2}{-\sqrt{2}/2} = 1$

$\csc\dfrac{5\pi}{4} = -\sqrt{2}$, $\quad \sec\dfrac{5\pi}{4} = -\sqrt{2}$, $\quad \cot\dfrac{5\pi}{4} = 1$

Example: Given $\sin\theta = \dfrac{3}{5}$ and $\theta$ is in Q II, find all other trig functions.

$\cos^2\theta = 1 - \sin^2\theta = 1 - \dfrac{9}{25} = \dfrac{16}{25}$

In Q II, cos is negative: $\cos\theta = -\dfrac{4}{5}$

$\tan\theta = \dfrac{3/5}{-4/5} = -\dfrac{3}{4}$

$\csc\theta = \dfrac{5}{3}$, $\quad \sec\theta = -\dfrac{5}{4}$, $\quad \cot\theta = -\dfrac{4}{3}$

4.3 Fundamental Trigonometric Identities

Reciprocal Identities:

\[\csc\theta = \frac{1}{\sin\theta}, \quad \sec\theta = \frac{1}{\cos\theta}, \quad \cot\theta = \frac{1}{\tan\theta}\]

Quotient Identities:

\[\tan\theta = \frac{\sin\theta}{\cos\theta}, \quad \cot\theta = \frac{\cos\theta}{\sin\theta}\]

Pythagorean Identities:

\(\sin^2\theta + \cos^2\theta = 1\) \(1 + \tan^2\theta = \sec^2\theta\) \(1 + \cot^2\theta = \csc^2\theta\)

Even/Odd Identities:

\(\sin(-\theta) = -\sin\theta \quad \text{(odd)}\) \(\cos(-\theta) = \cos\theta \quad \text{(even)}\) \(\tan(-\theta) = -\tan\theta \quad \text{(odd)}\)

The three Pythagorean identities are really just one identity in disguise.
Divide $\sin^2\theta + \cos^2\theta = 1$ by $\cos^2\theta$ → $\tan^2\theta + 1 = \sec^2\theta$.
Divide by $\sin^2\theta$ → $1 + \cot^2\theta = \csc^2\theta$.


Key Takeaways

  1. Radians are the natural unit for angles: $\pi$ rad $= 180°$. Use radians for arc length ($s = r\theta$) and sector area ($A = \tfrac{1}{2}r^2\theta$).
  2. The unit circle defines $\cos\theta$ and $\sin\theta$ as coordinates: point $(\cos\theta, \sin\theta)$ on $x^2 + y^2 = 1$.
  3. SOH-CAH-TOA for right triangles; the unit circle extends trig to all angles.
  4. Special angles ($30°$, $45°$, $60°$) come from the $1$-$\sqrt{3}$-$2$ and $1$-$1$-$\sqrt{2}$ triangles.
  5. Reference angles let you compute trig values in any quadrant from Q I values.
  6. ASTC (All-Sine-Tangent-Cosine) tells you which functions are positive in each quadrant.
  7. Pythagorean Identity: $\sin^2\theta + \cos^2\theta = 1$ — the most important trig identity.
  8. Even/Odd: Cosine is even ($\cos(-\theta) = \cos\theta$); sine and tangent are odd.

Practice Questions

Q1. Convert $225°$ to radians.

Answer:
$225° \times \dfrac{\pi}{180°} = \dfrac{225\pi}{180} = \dfrac{5\pi}{4}$

Q2. Find the arc length subtended by a central angle of $\dfrac{3\pi}{4}$ radians in a circle of radius 8 cm.

Answer:
$s = r\theta = 8 \cdot \dfrac{3\pi}{4} = 6\pi \approx 18.85$ cm

Q3. Find all six trig functions of $\theta = \dfrac{2\pi}{3}$.

Answer:
Q II, reference angle $= \pi - \dfrac{2\pi}{3} = \dfrac{\pi}{3}$.

$\sin\dfrac{2\pi}{3} = \dfrac{\sqrt{3}}{2}$, $\quad \cos\dfrac{2\pi}{3} = -\dfrac{1}{2}$

$\tan\dfrac{2\pi}{3} = \dfrac{\sqrt{3}/2}{-1/2} = -\sqrt{3}$

$\csc\dfrac{2\pi}{3} = \dfrac{2\sqrt{3}}{3}$, $\quad \sec\dfrac{2\pi}{3} = -2$, $\quad \cot\dfrac{2\pi}{3} = -\dfrac{\sqrt{3}}{3}$

Q4. If $\cos\theta = -\dfrac{5}{13}$ and $\theta$ is in Quadrant III, find $\sin\theta$ and $\tan\theta$.

Answer:
$\sin^2\theta = 1 - \cos^2\theta = 1 - \dfrac{25}{169} = \dfrac{144}{169}$

In Q III, sin is negative: $\sin\theta = -\dfrac{12}{13}$

$\tan\theta = \dfrac{\sin\theta}{\cos\theta} = \dfrac{-12/13}{-5/13} = \dfrac{12}{5}$

Q5. Find the reference angle for $315°$ and use it to evaluate $\cos(315°)$.

Answer:
$315°$ is in Q IV. Reference angle $= 360° - 315° = 45°$.

In Q IV, cosine is positive.

$\cos(315°) = +\cos(45°) = \dfrac{\sqrt{2}}{2}$

Q6. A wheel of radius 3 feet makes 200 revolutions per minute. Find the linear speed of a point on the rim in feet per second.

Answer:
$\omega = 200 \times 2\pi = 400\pi$ rad/min

$v = r\omega = 3 \times 400\pi = 1200\pi$ ft/min

Convert to ft/sec: $\dfrac{1200\pi}{60} = 20\pi \approx 62.83$ ft/sec.


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