Chapter 8 β Periodic Functions
Sine and cosine arenβt just about triangles β they are the building blocks of periodic phenomena: sound waves, alternating current, tidal patterns, seasonal temperatures, and even the motion of a Ferris wheel. This chapter teaches you to graph all six trig functions and their transformations, and introduces inverse trigonometric functions for solving equations.
Table of Contents
1 β Graphs of Sine and Cosine
- 1.1 The Basic Sine Graph
- 1.2 The Basic Cosine Graph
- 1.3 Amplitude
- 1.4 Period
- 1.5 The General Sinusoidal Function
- 1.6 Phase Shift (Horizontal Shift)
- 1.7 Vertical Shift (Midline)
- 1.8 Graphing Strategy
2 β Graphs of the Other Trigonometric Functions
- 2.1 The Tangent Function
- 2.2 The Cotangent Function
- 2.3 The Secant Function
- 2.4 The Cosecant Function
3 β Inverse Trigonometric Functions
Glossary
| Term | Definition |
|---|---|
| Periodic function | A function that repeats its values at regular intervals: $f(x + P) = f(x)$ |
| Period ($P$) | The smallest positive value such that $f(x + P) = f(x)$ for all $x$ |
| Amplitude | Half the distance between the maximum and minimum: $|a|$ in $y = a\sin(bx)$ |
| Midline | The horizontal line halfway between max and min: $y = d$ in $y = a\sin(bx - c) + d$ |
| Phase shift | The horizontal displacement: $\dfrac{c}{b}$ in $y = a\sin(bx - c) + d$ |
| Frequency | Number of cycles per unit: $f = 1/P$ |
| $\sin^{-1}(x)$ / $\arcsin(x)$ | Inverse sine; returns angle in $[-\pi/2, \pi/2]$ |
| $\cos^{-1}(x)$ / $\arccos(x)$ | Inverse cosine; returns angle in $[0, \pi]$ |
| $\tan^{-1}(x)$ / $\arctan(x)$ | Inverse tangent; returns angle in $(-\pi/2, \pi/2)$ |
1 β Graphs of Sine and Cosine
1.1 The Basic Sine Graph
$y = \sin x$ has these properties:
| Property | Value | |βββ-|ββ-| | Domain | $(-\infty, \infty)$ | | Range | $[-1, 1]$ | | Period | $2\pi$ | | Amplitude | $1$ | | $x$-intercepts | $x = n\pi$ for integer $n$ | | Maximum | $y = 1$ at $x = \dfrac{\pi}{2} + 2n\pi$ | | Minimum | $y = -1$ at $x = \dfrac{3\pi}{2} + 2n\pi$ | | Symmetry | Odd ($\sin(-x) = -\sin x$); origin symmetry |
Key points for one period $[0, 2\pi]$:
$(0, 0) \to \left(\dfrac{\pi}{2}, 1\right) \to (\pi, 0) \to \left(\dfrac{3\pi}{2}, -1\right) \to (2\pi, 0)$
1.2 The Basic Cosine Graph
$y = \cos x$ has these properties:
| Property | Value | |βββ-|ββ-| | Domain | $(-\infty, \infty)$ | | Range | $[-1, 1]$ | | Period | $2\pi$ | | Amplitude | $1$ | | Maximum | $y = 1$ at $x = 2n\pi$ | | Minimum | $y = -1$ at $x = \pi + 2n\pi$ | | Symmetry | Even ($\cos(-x) = \cos x$); $y$-axis symmetry |
Key points for one period $[0, 2\pi]$:
$(0, 1) \to \left(\dfrac{\pi}{2}, 0\right) \to (\pi, -1) \to \left(\dfrac{3\pi}{2}, 0\right) \to (2\pi, 1)$
Relationship: $\cos x = \sin!\left(x + \dfrac{\pi}{2}\right)$. The cosine graph is the sine graph shifted left by $\dfrac{\pi}{2}$.
1.3 Amplitude
| Amplitude $= | a | $ in $y = a\sin(bx)$ or $y = a\cos(bx)$. |
It measures the height from the midline to the peak (or trough).
-
$ a > 1$: vertical stretch (taller waves) -
$0 < a < 1$: vertical compression (shorter waves) - $a < 0$: reflection over the $x$-axis (flipped)
1.4 Period
| Period $= \dfrac{2\pi}{ | b | }$ in $y = a\sin(bx)$ or $y = a\cos(bx)$. |
-
$ b > 1$: horizontal compression (shorter period, faster oscillation) -
$0 < b < 1$: horizontal stretch (longer period, slower oscillation)
Example: $y = 3\sin(2x)$.
| Amplitude $= | 3 | = 3$. Period $= \dfrac{2\pi}{2} = \pi$. |
The wave oscillates between $-3$ and $3$, completing a full cycle every $\pi$ units.
1.5 The General Sinusoidal Function
| Parameter | Effect | Formula | |ββββ|βββ|βββ| | $a$ | Amplitude | $|a|$ | | $b$ | Period | $P = \dfrac{2\pi}{|b|}$ | | $c$ | Phase shift | $\dfrac{c}{b}$ (right if positive) | | $d$ | Vertical shift / Midline | $y = d$ |
1.6 Phase Shift (Horizontal Shift)
Phase Shift $= \dfrac{c}{b}$ in $y = a\sin(bx - c) + d$.
Factor out $b$: $y = a\sin!\left[b!\left(x - \dfrac{c}{b}\right)\right] + d$
The graph shifts right by $\dfrac{c}{b}$ if $c > 0$, or left if $c < 0$.
Example: $y = \sin!\left(2x - \dfrac{\pi}{3}\right)$.
Phase shift $= \dfrac{\pi/3}{2} = \dfrac{\pi}{6}$ to the right.
Period $= \dfrac{2\pi}{2} = \pi$.
The starting point shifts from $x = 0$ to $x = \dfrac{\pi}{6}$.
1.7 Vertical Shift (Midline)
The constant $d$ shifts the entire graph up or down. The midline is $y = d$ (the horizontal line the wave oscillates around).
-
Maximum value: $d + a $ -
Minimum value: $d - a $
Example: $y = -2\cos(x) + 3$.
| Amplitude: $ | -2 | = 2$. Midline: $y = 3$. Reflection (since $a < 0$). |
Max: $3 + 2 = 5$ (but at the usual cosine minimum positions because of reflection). Min: $3 - 2 = 1$.
1.8 Graphing Strategy
- Identify $a$, $b$, $c$, $d$.
-
Compute amplitude $= a $, period $= 2\pi/ b $, phase shift $= c/b$, midline $= d$. - Find the starting point (phase shift) and ending point (phase shift + period).
- Divide the period into four equal parts to locate the quarter-points.
- Plot the five key points (start, quarter, half, three-quarter, end) using sine or cosine pattern.
- Apply reflection if $a < 0$.
- Extend the pattern in both directions.
Example: Graph $y = 3\sin!\left(\dfrac{\pi}{2}x - \pi\right) + 1$.
$a = 3$, $b = \dfrac{\pi}{2}$, $c = \pi$, $d = 1$.
- Amplitude: $3$
- Period: $\dfrac{2\pi}{\pi/2} = 4$
- Phase shift: $\dfrac{\pi}{\pi/2} = 2$ (right)
- Midline: $y = 1$
Five key points (starting at $x = 2$, period $= 4$, so quarter $= 1$):
| $x$ | $y$ | |β|β| | $2$ | $1$ (midline, going up) | | $3$ | $4$ (max: $1 + 3$) | | $4$ | $1$ (midline, going down) | | $5$ | $-2$ (min: $1 - 3$) | | $6$ | $1$ (midline, one full cycle) |
2 β Graphs of the Other Trigonometric Functions
2.1 The Tangent Function
$y = \tan x = \dfrac{\sin x}{\cos x}$
| Property | Value | |βββ-|ββ-| | Domain | All reals except $x = \dfrac{\pi}{2} + n\pi$ | | Range | $(-\infty, \infty)$ | | Period | $\pi$ | | Vertical asymptotes | $x = \dfrac{\pi}{2} + n\pi$ | | $x$-intercepts | $x = n\pi$ | | Symmetry | Odd (origin symmetry) | | Behavior | Increasing on each branch |
Key points in one period $\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)$:
$\left(-\dfrac{\pi}{4}, -1\right)$, $(0, 0)$, $\left(\dfrac{\pi}{4}, 1\right)$
Transformed tangent: $y = a\tan(bx - c) + d$
-
Period $= \dfrac{\pi}{ b }$ - Phase shift $= \dfrac{c}{b}$
-
Vertical stretch by $ a $; vertical shift $d$
Tangent has no amplitude β its range is all real numbers. The parameter $a$ controls the vertical stretch (steepness), not a bounded amplitude.
2.2 The Cotangent Function
$y = \cot x = \dfrac{\cos x}{\sin x}$
| Property | Value | |βββ-|ββ-| | Domain | All reals except $x = n\pi$ | | Range | $(-\infty, \infty)$ | | Period | $\pi$ | | Vertical asymptotes | $x = n\pi$ | | $x$-intercepts | $x = \dfrac{\pi}{2} + n\pi$ | | Symmetry | Odd | | Behavior | Decreasing on each branch |
Cotangent is like tangentβs mirror image β it decreases where tangent increases.
2.3 The Secant Function
$y = \sec x = \dfrac{1}{\cos x}$
| Property | Value | |βββ-|ββ-| | Domain | All reals except $x = \dfrac{\pi}{2} + n\pi$ | | Range | $(-\infty, -1] \cup [1, \infty)$ | | Period | $2\pi$ | | Vertical asymptotes | $x = \dfrac{\pi}{2} + n\pi$ (where $\cos x = 0$) | | No $x$-intercepts | (secant is always $\ge 1$ or $\le -1$) | | Symmetry | Even |
Graphing secant from cosine: Draw the cosine curve lightly. The secant graph has U-shaped branches opening away from the $x$-axis, with vertices at the max/min of cosine, and vertical asymptotes where cosine crosses zero.
2.4 The Cosecant Function
$y = \csc x = \dfrac{1}{\sin x}$
| Property | Value | |βββ-|ββ-| | Domain | All reals except $x = n\pi$ | | Range | $(-\infty, -1] \cup [1, \infty)$ | | Period | $2\pi$ | | Vertical asymptotes | $x = n\pi$ (where $\sin x = 0$) | | Symmetry | Odd |
Graph cosecant the same way as secant β draw sine lightly, then draw U-branches at each peak/trough, with asymptotes at sineβs zeros.
3 β Inverse Trigonometric Functions
3.1 Why We Need Restricted Domains
Sine, cosine, and tangent are not one-to-one over their full domains (they fail the horizontal line test). To define an inverse, we restrict the domain to an interval where the function is one-to-one.
3.2 Inverse Sine (Arcsine)
Inverse Sine: $y = \sin^{-1}(x) = \arcsin(x)$
βWhat angle in $\left[-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right]$ has sine equal to $x$?β
| Property | Value |
|---|---|
| Domain | $[-1, 1]$ |
| Range | $\left[-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right]$ |
\(\sin^{-1}(x) = \theta \iff \sin\theta = x \text{ and } -\frac{\pi}{2} \le \theta \le \frac{\pi}{2}\)
| Expression | Answer | Reasoning | |β|β|β| | $\sin^{-1}(1)$ | $\dfrac{\pi}{2}$ | $\sin\dfrac{\pi}{2} = 1$ | | $\sin^{-1}!\left(\dfrac{1}{2}\right)$ | $\dfrac{\pi}{6}$ | $\sin\dfrac{\pi}{6} = \dfrac{1}{2}$ | | $\sin^{-1}!\left(-\dfrac{\sqrt{2}}{2}\right)$ | $-\dfrac{\pi}{4}$ | $\sin!\left(-\dfrac{\pi}{4}\right) = -\dfrac{\sqrt{2}}{2}$ | | $\sin^{-1}(0)$ | $0$ | $\sin 0 = 0$ |
3.3 Inverse Cosine (Arccosine)
Inverse Cosine: $y = \cos^{-1}(x) = \arccos(x)$
βWhat angle in $[0, \pi]$ has cosine equal to $x$?β
| Property | Value |
|---|---|
| Domain | $[-1, 1]$ |
| Range | $[0, \pi]$ |
\(\cos^{-1}(x) = \theta \iff \cos\theta = x \text{ and } 0 \le \theta \le \pi\)
| Expression | Answer | |β|β| | $\cos^{-1}(0)$ | $\dfrac{\pi}{2}$ | | $\cos^{-1}!\left(-\dfrac{1}{2}\right)$ | $\dfrac{2\pi}{3}$ | | $\cos^{-1}(1)$ | $0$ | | $\cos^{-1}(-1)$ | $\pi$ |
3.4 Inverse Tangent (Arctangent)
Inverse Tangent: $y = \tan^{-1}(x) = \arctan(x)$
βWhat angle in $\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)$ has tangent equal to $x$?β
| Property | Value |
|---|---|
| Domain | $(-\infty, \infty)$ |
| Range | $\left(-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right)$ |
| Horizontal asymptotes | $y = -\dfrac{\pi}{2}$ and $y = \dfrac{\pi}{2}$ |
\(\tan^{-1}(x) = \theta \iff \tan\theta = x \text{ and } -\frac{\pi}{2} < \theta < \frac{\pi}{2}\)
| Expression | Answer | |β|β| | $\tan^{-1}(1)$ | $\dfrac{\pi}{4}$ | | $\tan^{-1}(-1)$ | $-\dfrac{\pi}{4}$ | | $\tan^{-1}(0)$ | $0$ | | $\tan^{-1}(\sqrt{3})$ | $\dfrac{\pi}{3}$ |
3.5 Composing Trig and Inverse Trig Functions
Cancellation Properties:
\(\sin(\sin^{-1}(x)) = x \quad \text{for } x \in [-1, 1]\) \(\sin^{-1}(\sin(x)) = x \quad \text{for } x \in \left[-\frac{\pi}{2}, \frac{\pi}{2}\right]\)
Same pattern for cosine and tangent with their respective restricted ranges.
Outside the restricted range, the inverse doesnβt simply βcancelβ:
$\sin^{-1}!\left(\sin\dfrac{5\pi}{6}\right) \ne \dfrac{5\pi}{6}$ because $\dfrac{5\pi}{6} \notin \left[-\dfrac{\pi}{2}, \dfrac{\pi}{2}\right]$.
Instead: $\sin\dfrac{5\pi}{6} = \dfrac{1}{2}$, so $\sin^{-1}!\left(\dfrac{1}{2}\right) = \dfrac{\pi}{6}$.
Example: Evaluate $\cos!\left(\sin^{-1}!\left(\dfrac{3}{5}\right)\right)$.
Let $\theta = \sin^{-1}!\left(\dfrac{3}{5}\right)$, so $\sin\theta = \dfrac{3}{5}$ with $\theta \in$ Q I.
$\cos\theta = \sqrt{1 - \sin^2\theta} = \sqrt{1 - \dfrac{9}{25}} = \sqrt{\dfrac{16}{25}} = \dfrac{4}{5}$
Answer: $\dfrac{4}{5}$
Example: Evaluate $\tan!\left(\cos^{-1}!\left(-\dfrac{5}{13}\right)\right)$.
Let $\theta = \cos^{-1}!\left(-\dfrac{5}{13}\right)$, so $\cos\theta = -\dfrac{5}{13}$ with $\theta \in$ Q II (since cosine is negative and $\theta \in [0, \pi]$).
$\sin\theta = \sqrt{1 - \dfrac{25}{169}} = \sqrt{\dfrac{144}{169}} = \dfrac{12}{13}$ (positive in Q II)
$\tan\theta = \dfrac{12/13}{-5/13} = -\dfrac{12}{5}$
Key Takeaways
- Sine and cosine are periodic with period $2\pi$, amplitude $1$, range $[-1, 1]$.
-
General form: $y = a\sin(bx - c) + d$ β amplitude $ a $, period $2\pi/ b $, phase shift $c/b$, midline $y = d$. - Five-point method: Divide one period into quarters to plot sine/cosine efficiently.
- Tangent and cotangent have period $\pi$, range $(-\infty, \infty)$, and vertical asymptotes.
- Secant and cosecant are reciprocals of cosine and sine β graph them using the parent functionβs curve.
- Inverse trig functions restrict the domain to produce a one-to-one function:
- $\sin^{-1}$: range $[-\pi/2, \pi/2]$
- $\cos^{-1}$: range $[0, \pi]$
- $\tan^{-1}$: range $(-\pi/2, \pi/2)$
- Composition caution: $\sin^{-1}(\sin x) = x$ only when $x$ is in the restricted range.
Practice Questions
Q1. Find the amplitude, period, phase shift, and midline of $y = -4\cos!\left(3x + \dfrac{\pi}{2}\right) + 2$.
Answer:
$a = -4$, $b = 3$, $c = -\dfrac{\pi}{2}$, $d = 2$.
-
Amplitude: $ -4 = 4$ - Period: $\dfrac{2\pi}{3}$
- Phase shift: $\dfrac{-\pi/2}{3} = -\dfrac{\pi}{6}$ (left $\dfrac{\pi}{6}$)
- Midline: $y = 2$
- Max: $2 + 4 = 6$, Min: $2 - 4 = -2$
Q2. Write the equation of a sine function with amplitude 5, period $4\pi$, phase shift $\pi$ to the right, and midline $y = -3$.
Answer:
$|a| = 5 \Rightarrow a = 5$
$P = \dfrac{2\pi}{b} = 4\pi \Rightarrow b = \dfrac{1}{2}$
Phase shift $= \dfrac{c}{b} = \pi \Rightarrow c = \dfrac{\pi}{2}$
\(y = 5\sin\!\left(\frac{1}{2}x - \frac{\pi}{2}\right) - 3\)
Q3. Find the period and asymptotes of $y = \tan!\left(\dfrac{\pi}{4}x\right)$.
Answer:
Period $= \dfrac{\pi}{\pi/4} = 4$
Asymptotes: $\dfrac{\pi}{4}x = \dfrac{\pi}{2} + n\pi \Rightarrow x = 2 + 4n$
First few: $x = -2, 2, 6, 10, \ldots$
Q4. Evaluate: $\cos^{-1}!\left(-\dfrac{\sqrt{3}}{2}\right)$.
Answer:
Need $\theta \in [0, \pi]$ with $\cos\theta = -\dfrac{\sqrt{3}}{2}$.
Reference angle: $\dfrac{\pi}{6}$ (since $\cos\dfrac{\pi}{6} = \dfrac{\sqrt{3}}{2}$). In Q II: $\theta = \pi - \dfrac{\pi}{6} = \dfrac{5\pi}{6}$.
Q5. Evaluate: $\sin!\left(\tan^{-1}!\left(\dfrac{7}{24}\right)\right)$.
Answer:
Let $\theta = \tan^{-1}!\left(\dfrac{7}{24}\right)$, so $\tan\theta = \dfrac{7}{24}$ with $\theta$ in Q I.
Right triangle: opposite $= 7$, adjacent $= 24$, hypotenuse $= \sqrt{49 + 576} = \sqrt{625} = 25$.
$\sin\theta = \dfrac{7}{25}$
Q6. Evaluate: $\sin^{-1}!\left(\sin\dfrac{7\pi}{6}\right)$.
Answer:
$\sin\dfrac{7\pi}{6} = -\dfrac{1}{2}$ (Q III, reference angle $\dfrac{\pi}{6}$).
$\sin^{-1}!\left(-\dfrac{1}{2}\right) = -\dfrac{\pi}{6}$ (must be in $[-\pi/2, \pi/2]$).
Answer: $-\dfrac{\pi}{6}$